Question

1. Answer the following questions about solutions of HCL and Ba(OH), a. Draw a particulate level diagram of HCl(aq). Show five particles of HCl. You do not need to include the water in your diagram. b. Draw a particulate level diagram of Ba(OH), (aq). Show five particles of Ba(OH), You do not need to include water in your diagram. C. Calculate the pH of 0.0100 M HCL d. Calculate the pH of 0.0100 M Ba(OH)2

Answer 1

a) The particulate level diagram of HCl will have H+ ions [5] and 5 ions of Cl- ions

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b) The particulate level diagram of Ba(OH)2 will have Ba(2+) ions [5] and 10 ions of OH- ions

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c)

pH of 0.0100 M HCl

Since HCl is a strong acid, hence it will dissociate completely in the solution

pH = -log[H+] = -log[0.0100] = 2

d)

pH of 0.0100 M Ba(OH)2

Since Ba(OH)2 is a strong base, hence it will dissociate completely in the solution

pOH = -log[OH-] = -log[0.0200] = 1.70

pH = 14 - pOH = 14 - 1.70 = 12.30

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