Question

Solid phosphorus (P) and chlorine (Cl2) gas react to form solid phosphorus pentachloride (PC13). Suppose you have 13.0 mol of P and 1.0 mol of Cl, in a reactor. Calculate the largest amount of PC1, that could be produced. Round your answer to the nearest 0.1 mol. I mol x | ?

Answer 1

Answer:

Explanation:

A mole ratio is ​the ratio between the amounts in moles of any two compounds involved in a chemical reaction. The mole ratio can be determined by examining the coefficients in front of formulas in a balanced chemical equation.

Step 1: write the balanced chemical equation.

2 P(s) + 5 Cl2(g) ----------> 2 PCl5(s)

Step 2: Extract the data

Given ,

Moles of P = 13 mol

Moles of Cl2 = 1 mol

Step 3: Determine the limiting reagent

2 P(s) + 5 Cl2(g) ----------> 2 PCl5(s)

According to the reaction we need
5 mol of Cl2 requires for 2 mol of P
so, for 1 mol of Cl2  we will need =(2 mol of P / 5 mol of Cl2 )× 1 mol of Cl2 = 0.4 mol of P
Since we need only 0.4 mol of P hence P is in excess ( since given =13 mol ) and Cl2 limiting reagent.

so the amount of product will formed according to the limiting reagent ( i.e Cl2 amount )

Step 3: Calculate the maximum moles of PCl5

2 P(s) + 5 Cl2(g) ----------> 2 PCl5(s)

According to the reaction:
5 mol of Cl2 produce 2 mol of  PCl5
so, 1 mol of Cl2 will produce =( 2 mol of PCl5 / 5 mol of Cl2 ) × 1 mol of Cl2 = 0.4 mol of PCl5

Hence, the maximum amount of PCl5 that can be produced = 0.4 mol