Given 1.55 g of solute
25 ml of solvent is water
Temprature T2= 100.850°C
Density of H2O is = 0.997g/ml
Now, from the formula
∆Tb = Kb. m ........ Where m is molality
Kb is constant 0.512
∆Tb is elevation in boiling Point
Now , mass of water = density* volume of water
= 0.997*25 = 24.925 g
Put velues in above formula we get
100.850 - 100 = 0.512 * m
m = 1.660
From above number of moles = mass / molar mass
Hence, molar mass = 1.55/1.660*24.925*10^-3
Molar mass = 1.55/41.3755*10^-3
Molar mass = 37.46 g
Hence molar mass is 37.46 g
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