Question

The decomposition of N,Os can be described by the equation t(s) 0 2N20: (soln) 4NO2 (soln) + 02 (8) 135 476 [N, 05] (M) 2.242 2.059 1.662 1.343 Consider the data in the table for the reaction at 45 °C in carbon tetrachloride solution. 815 Given the data, calculate the average rate of reaction for each successive time interval. What is the average rate of reaction for the time interval from 0 s to 135 s? average rate of reaction: M /S What is the average rate of reaction for the time interval from 135 s to 476 s? average rate of reaction: M/S What is the average rate of reaction for the time interval from 476 s to 815 s?

Answer 1

Soluth:- Decomposition of 2N₂O5 (soluth) N₂ Os can be given - 4NO2 (solutn) & Oz (0, by Givem, tco I Na Os (m) 2.242 2.059 1.662 1:343 135 476 dist! 1815 D Now, we know, Average rate =- £ l SA Where '2' is stio chiometric coefficient. • Average rate for time Interval o to 3582 e rates 2-242 A Average ruke [ 2-06852022] 3+ (-01 ] $(pore] 0,18 0.00136 Average rate = 6.8810" molatsi or, Average rate of reaction : / 6.8x10" M srl

Average rate of reaction for interval 1358 to 47688 Conc. at 135(0) = 2:05am cone of N2Os at 476s s 1.662 m Average rates ad r 1.662-2.059 476 -135 class -0.397 :5 [ 534997 ] Dodao 341 341 or Avg. rate s 5.82 x 104 M srl i Average rate of reaction: [5.82x104 m si

- Average rate for 4768 to 8158. time interval Conc. of N2O5 at 45768 = 1.662.m cone of N2O5 at 8.58 = 1:343 m Average rate -Ź[SNoss] 1-343-1.667 -476 -6.319 7 0.1595 or Avg. rate st L 339 39 oo, Aug.rate = 4.7x10 m st Average rate of reaction: 4:48 104 mot
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