Question

The decomposition of N can be described by the equation t (s) DN205 (M) 2.50 2N,os (soln) -3 4NO2 (soln) 0, (g) 165 2.25 446 1.89 Given these data for the reaction at 45°C in carbon tetrachloride solution, 805 1.51 calculate the average rate of reaction for each successive time interval. L Interval 0 s to 165 s 165 s to 446 s 446 s to 805 s Number Number Reaction rate: D Number

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Answer 1

Equation: 2N, O-- > 4NO + O - -1dLo,]. +1dMo,]do] Rate of thereacti on- --+ 2 dt 4 dt dt Interval: 0 s to 165 s 세NA] 2 dt Rate of reaction =- 1 (2.25 M-2.50M) 2 (165 s- 0 s) -7.58x104 M/s Interval: 165 s to 446 s Rate of reacti on - - 2 dt 1 (1.89 M-2.25M) 2 (446 s-165 s) Interval: 446 s to 805 s d[N20, Rate of reaction = dt 1 (1.51M-1.89M) 2 (805 s- 446 s) = 5.29×10-4 M/s Equation: A 2B Rate of thereaction dIA +1dB] dt 2 dt _d4] dt Rate of reaction = - (0.110 M-0.630 M) (332 s-0 s) = 0.00 157 M/s -1.57 x103 MIs