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Consider the following equilibrium: N2(g) + 3H2 (g) = 2NH3(g) AG°= - 34. kJ Now suppose a reaction vessel is filled with 2.01

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48.2 (5.745 120 X 3 IME (5.74)? (2.01) x4329 - 32.9476 87.0129 Downloa eta ena = 0.3987; pl PH₂ = 0.72 atm Under these conditAG = -34 KI. . Convert unit from KJ tot AG = -34kJ X10001/161 AG = - 34000 DGP - LRTinke :-34000= -8.314 Trolls X ( 812 + 27

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