Question

Determine the molar solubility of CuCl in a solution containing 0.030 M LiCl. K_sp (CuCl) = 1.7×10^-7.

Determine the molar solubility of CuCl in a solution containing 0.030 M LiCl. K_sp (CuCl) = 1.7×10^-7.

4.1×10-4 M

2.9×10-14 M

5.7×10−6 M

5.1×10−9 M

4.7×10−5 M

Answer 1

Answers Stepat The concentration of ci dissociated from Lick is 0.030 m where as concentration of ci con dissociated from cucl taxon as is'. The total concentration of cl us one sum of the concentra- tion of ci formed from Licl and ci formed from cucl. til [lick] = cuch a [cuch) = eit & ci [lit] a [ei] & 0.030 m cut & ci [cat] = [ci] = s Total [er) - (S+ 0.030) m Step-a of Cact can be determined using molar she solubility expression cucl - cut & ci Ksp = [enty [oi] Here Ksp = 1.7 x 107 [cat] =s

[1] = (+0.030) m Then 1-7 X107 S( 5 +0.030) Hene (s+0.080) appoonimately equal to 0.030 1.7x107 = Sx 0.030 S = 1.7 x 1077 0.030 5.7 x 106m Answer 5.7 x 106m