QUESTION 8 Calculate the pH of a solution that is 0.384 M CH3COOH and 0.374 M...
Calculate the pH of a buffer solution containing 0.100 M CH3COOH and 0.100 M CH3COONa ; Ka of CH3COOH = 1.8 x 10-5
Question 8 (2 points) A 1.00-L of a buffer contains 0.076 M CH3COOH(aq) and 0.214 M CH3COONa(aq); Kalacetic acid) - 1.8 x 10-5. Calculate the pH after the addition of 0.003 moles HCI. Provide your answer to two places after the decimal.
What is the pH of a solution prepared by mixing 25.00 mL of 0.10 M CH3COOH with 25.00 mL of 0.050 M CH3COONa? Assume that the volume of the solutions are additive and that Ka = 1.8 x 10-5 for CH3COOH.
What is the pH of a 0.25 M solution of NaCH3COO (Ka (CH3COOH) = 1.8 * 10-5)? Instruction: Please have two decimal places for your answer
What is the pH of a buffer that consists of 0.45 M CH3COOH and 0.35 M CH3COONa? Ka = 1.8 x 10-5 So the answer is 4.64. However, I was under the impression that it is Ka * (base/acid). So wouldn't that be 1.8 x 10^-5 * (.35/.45)? Isn't the CH3COONa the base? Someone please explain. Thank you.
Question 6 (2 points) A 1.00-L of a buffer contains 0.316 M CH3COOH(aq) and 0.315 M CH3COONa(aq); K (acetic acid) = 1.8 x 10-5. Calculate the pH after the addition of 0.009 moles HCI. Provide your answer to two places after the decimal. Your Answer: Answer
Question 12 1 pts Calculate the pH of a solution obtained by mixing 60.79 mL of 0.11 M CH3COOH with 12.47 mL of 0.12 M NaOH. (K,(CH3COOH) = 1.8 x 10-5) Enter your answer to 2 decimal places. For example, if your answer is pH = 12, enter 12.00
QUESTION 9 The pH of 0.50 M acetic acid is 2.52. Calculate the change in pH when 0.91 g of CH3COONa (FW - 82.03 g/mol) is added to 11.1 mL of 0.50 M acetic acid. CH3COOH. Ignore any changes in volume. The Ka value for CH3COOH is 1.8 x 10-5
Calculate the approximate pH of an aqueous solution of a mixture of CH3COOH, 0.27 M, and CH3COONa, 0.15 M, at 25°C. (Note: consider one decimal place for the pH answer.) pKa = 4.76.
4. Calculate [H30*], [OH-], pH and pOH of a 0.5 M CH3COOH solution, Ka = 1.8 x 10-5.