a)The balanced chemical equation will be:
2Al + 3Cl2 ---> 2AlCl3
b) Given : 30.0g of Al reacts with Chlorine gas
To find the mass of aluminium chloride produced from aluminium, we need to find the number of moles of aluminium for which we use the formula
number of moles = mass / molar mass of Al
= 30g/26.982(g/mol) = 1.112 moles of Al
Hence if 1.112 moles of Al is used in the reaction , then 1.112 moles of aluminium chloride will be produced since the molar ratio of Al:AlCl3 is 1:1 (from balanced chemical equation)
Now to find the number of grams of aluminium chloride produced we use the formula again,
Moles of AlCl3 = mass/molar mass
Mass = moles * molar mass of AlCl3
= 1.112 * ( 26.982 + (3*35.453))
= 1.112 * 133.341
= 148.275 grams
Hence 148.275 grams of Aluminium chloride will be produced if 30.0g i.e., 1.112 moles of aluminium is made to react with chlorine gas.
Hope this helps!
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