Question

i already know they answer please explain your solutions

ID: A fer- a solut monione blir rw Name: was 11. If 0.40 g of solid NaOH is added to 1.0 liter of a buffer solution that is 0.10 Min CH,COOH and 0.10 Min NaCH,COO, how will the pH of the solution change? a. The pH increases from 4.74 to 4.83. b. The pH decreases from 7.00 to 4.83. c. The pH does not change. d. The pH decreases from 4.74 to 4.65. The nH increases from 4.74 to 7.00. ind hy mixing 100. mL of 0.10 M HF and 200.mL of 0.10 MKF. 719 Headbo

Ka for CH3COOH = 1.8x10^-5

pka i calculated 4.74

Answer 1

The correct answer is -option (a)

# Ka for CH3COOH = 1.8 x10-5 .. bka = -logka = -log (1-8810-5) = 4.74 Buffer solution contains 0.10 M CH3 COOH and 0-10M Na (ht3cco : Volume of buffer solution - 1.0 Lit. .. Now, amount of CH3COOH = 0.1 mol x 1.0L = 0.1 mol amount of CHE COONa = 0.1 mol x10L = 0,1 mol ..pH of buffer solution 7 PH = pka + log felt3 COONa] 54.74 + a O = 4.79 [сатн] : :: pH of buffer solution - 4.74 • After addition of 0.40 g of solid NaOH :- Malar mass of NaOH = 40 g.mor" 4. Amount of NaOH added = 8o4 Lens.0.01 mol : 108 01 Yogi moi? This added NaOH reacts with CH3COOH and form eH3 COONG & 120 · 50, amount of aud decreases & amount of salt increases. NaOH (added) + CH3 COOH (buffer) + CH3COONa + H20 0.01 mol 0.04 mol 0-01 mol - Nows amount of CH3 COOH = (0-1-0-01] = 0.og mo! amount of CH3 COUNQ = (0.1 +0.01] = D.ll mol pH = pka + log Iltz couna] og [CH3COUH] 479 + log con ) = 4.83 The correct answer is 7 @ The pH increases from 4.74 to 4.83 .

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