Question

Exercise 9.108 Part A The particle nature of light was first proposed by Albert Einstein, who suggested that light could be described as a stream of particles called photons. A photon of wavelength has an energy (E) given by the following equation: E= hc/1, where E is the energy of the photon in J, h is Planck's constant (6.626 x 10–34 J·s), and c is the speed of light (3.00 x 108 m/s). Calculate the energy of 3mol of photons with a wavelength of 562nm. O AL * o ? Submit Submit Previous Answers Request Answer Previ X Incorrect; Try Again; 5 attempts remaining

Answer 1

Wavelength : 1 = 562 nm = 562 X10-9 mi lom = 10-9m) E = he E = energy of one h: Planck's constant = (a speed of light = photon 6.626 X 10 34 Is 3.00 x 108 mis 3.00 x 108 mis = 6.626 X10-34 JS X 562 x 10-9m 3.54 x 10-19 J E= Viumber of photons = number of moles of photon = 3 mol In I mole of photon, there are 6.023X1023 photons Avogadro's number In 3 mole of photon, number of photons & = 6.023 X 10 23 X 3 mol Imol = 18.069 X1023 Energy of 3 mol of = number of protons X energy of I photon photons in 3 mol = 18.069 X 10 23 X 3.548 10-19 I - 6.396 X 105 I = 6.40 X 1055 - Answer Please Rate