Select the pair of reactants that will react. H2(g) + H+(aq) MnCl2(aq) + Cr(s) – AlCl3(aq)...
Use the tabulated electrode potentials to calculate K for the oxidation of nickel by H+: Ni(s)+2H+(aq)→Ni2+(aq)+H2(g) Express your answer using two significant figures. Standard reduction half-cell potentials at 25∘C Half-reaction E∘ (V) Half-reaction E∘ (V) Au3+(aq)+3e−→Au(s) 1.50 Fe2+(aq)+2e−→Fe(s) −0.45 Ag+(aq)+e−→Ag(s) 0.80 Cr3+(aq)+e−→Cr2+(aq) −0.50 Fe3+(aq)+3e−→Fe2+(aq) 0.77 Cr3+(aq)+3e−→Cr(s) −0.73 Cu+(aq)+e−→Cu(s) 0.52 Zn2+(aq)+2e−→Zn(s) −0.76 Cu2+(aq)+2e−→Cu(s) 0.34 Mn2+(aq)+2e−→Mn(s) −1.18 2H+(aq)+2e−→H2(g) 0.00 Al3+(aq)+3e−→Al(s) −1.66 Fe3+(aq)+3e−→Fe(s) −0.036 Mg2+(aq)+2e−→Mg(s) −2.37 Pb2+(aq)+2e−→Pb(s) −0.13 Na+(aq)+e−→Na(s) −2.71 Sn2+(aq)+2e−→Sn(s) −0.14 Ca2+(aq)+2e−→Ca(s) −2.76 Ni2+(aq)+2e−→Ni(s) −0.23 Ba2+(aq)+2e−→Ba(s) −2.90 Co2+(aq)+2e−→Co(s) −0.28 K+(aq)+e−→K(s) −2.92 Cd2+(aq)+2e−→Cd(s)...
Consider the following reaction at 298K. 2+ 2 H+ (aq) + Sn (s) —> H2 (g) + Sn? (aq) Which of the following statements are correct? Choose all that apply. E° cell 0 The reaction is reactant-favored. AG° < 0 On=2 mol electrons OK> 1
94. The net ionic equation for the reaction, Cu(s) + 2HNO3(aq) - H2(g) + Cu(NO3)(aq) A) Cu(s) + H(aq) → H2(aq) +Cu? (aq) B) Cu(s) +2H(aq) → H2(g) +Cu2+ (aq) C) Cu(s) +2H (aq) H2(g) + Cu(aq) D) Cu(s) + H(aq) H2(g) + Cu(aq) X Question 13 of 100 Meme 51. Which of the following is TRUE? A) Hydrogen atom to hydrogen ion (H+)is reduction B) Oxygen atom to oxide ion(O2-) is reduction. C) tin atom to tin(IV) ion is...
Question 4 (1 point) Write the cell diagram for the reaction 2AgCl(s) + H2(g) --> 2Ag(s) + 2H+(aq) + 2C1-(aq) OPt(s) | H2(g)| H+(aq) || CI+(aq)| AgCl(s) | Ag(s) Pt(s) | H2(g)| H+(aq) || CI+(aq) | Ag(s) | Pt(s) O Ag(s) | AgCl(s) || H+(aq), Ci-(aq) | H2(g) | Pt(s) O Ag(s) | AgCl(s) | CI+(aq) || H+(aq)| H2(g) | Pt(s) Pt(s) Cl(aq), H(aq)| H2(g) || AgCl(s) Ag(s)
What product forms at the anode in the aqueous electrolysis of MnCl2? Cl2(g) Mn(s) H2(g) and OH -(aq) O2(g) and H+(aq)
39. Given: E +0.46 V Eo- +0.34 V Cu(s) + 2 Ag+ → 2 Ag (s) + Cu2. Cu2+ + H2 (g) → Cu (s) + 2 H' Find the standard potential for the cell reaction for 2 Ag + H2 (g)-2 Ag+2H +0.80 V b. a. +0.40 V +0.12 V d. c. -0.12 v none of these e. 40. Given: Fe (s) + 2 Ag' (aq) Fe (ag)+ 2 Ag (s) with E ell -1.24 V What is the...
A) Use tabulated electrode potentials to calculate ΔG∘ for the reaction. 2K(s)+2H2O(l)→H2(g)+2OH−(aq)+2K+(aq) B) (Refer to the following standard reduction half-cell potentials at 25∘C: VO2+(aq)+Ni2+(aq)2H+(aq)++2e−e−→ →Ni(s)VO2+(aq) +H2O(l)E∘=−0.23V E∘=0.99V) An electrochemical cell is based on these two half-reactions: Oxidation:Reduction:Ni(s)VO2+(aq,0.024M)+2H+(aq,1.4M)+e−→→Ni2+(aq,1.8M)+2e−VO2+(aq,1.8M)+H2O(l) Calculate the cell potential under these nonstandard concentrations. C) Standard reduction half-cell potentials at 25∘C Half-reaction E∘ (V ) Half-reaction E∘ (V ) Au3+(aq)+3e−→Au(s) 1.50 Fe2+(aq)+2e−→Fe(s) − 0.45 Ag+(aq)+e−→Ag(s) 0.80 Cr3+(aq)+e−→Cr2+(aq) − 0.50 Fe3+(aq)+3e−→Fe2+(aq) 0.77 Cr3+(aq)+3e−→Cr(s) − 0.73 Cu+(aq)+e−→Cu(s) 0.52 Zn2+(aq)+2e−→Zn(s) − 0.76...
Select the Redox Reactions: A) Mg + 2H+--> Mg2+ +H2(g) B) K2CO3(aq) + Sr(NO3)2(aq)--> SrCO3(s) + 2KNO3(aq) C) 2OH- + 2ClO-2 --> ClO2- + ClO3- + H2O D) H+ + OH- --> H2O E) KSCN (aq) + Fe(NO3)3(aq) --> FeSCN2+(aq) + KNO3 (aq) + 2NO3- (aq) F) AgCl(s) +2NH3(aq) --> Ag(NH3)2+ (aq) +Cl- (aq)
PQ-19. What is the balanced net ionic equation for the reaction of CuCl(aq) and H2(g)? (A) Cu?+(aq) + H2(g) → Cu(s) + 2H*(aq) CuCl2 + Ha > H (B) CuCl2(aq) + H2(g) → Cu(s) + 2HCl(aq) (C) Cu?"(aq) + Cl2(aq) + H2(g) → Cu(s) + 2H*(aq) + 2Cl(aq) cu +261 + 2H+ $ (D) Cu2+(aq) + 2CH(aq) + H2(g) → Cu(s) + 2H+ (aq) + 2CH(aq)
1.) Given the following notation for an electrochemical cell Pt(s) | H2(g) | H+(aq) || Ag+(aq) | Ag(s), what is the balanced overall (net) cell reaction? A. H2(g) + 2Ag(s) ® H+(aq) + 2Ag+(aq B. H2(g) + 2Ag+(aq) ® 2H+(aq) + 2Ag(s) C. H2(g) + Ag+(aq) ® H+(aq) + Ag(s D. 2H+(aq) + 2Ag(s) ® H2(g) + 2Ag+(aq) E. 2H+(aq) + 2Ag+(aq) ® H2(g) + 2Ag(s) 2.) Calculate E°cell for the following (nonspontaneous) reaction: Cd(s) + 2Fe3+(aq) ® 2Fe2+(aq) + Cd2+(aq) → A. -0.37...