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Two students calculated the AG transfer for propyl red at six temperatures between 282 K and 317 K and made a graph of AG tra

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Answer #1

We Know that,

\bigtriangleup G^o_{transfer}=\bigtriangleup H^o_{transfer}-T\bigtriangleup S^o_{transfer}

Which can be in form of y=mx+c

Here,

y=\bigtriangleup G^o_{transfer}

c=\bigtriangleup H^o_{transfer}

m=\bigtriangleup S^o_{transfer}

Given,

y=-0.0982x+21.915

Terefore,

303f2f93-83ac-4fd1-aff0-601e11441154.png

\bigtriangleup S^o_{transfer}=0.0982 \text{ kJ/mol.K}

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