Answer is HNO2/NO2-
Only weak acid and it's conjugate base can act as buffer but not strong acid like HCl.
An acid is used as buffer at a pH when
pH = -log(Ka)
Since for HNO2/NO2-,
pH = -log(4.0×10-4)
= 3.4
Since, it's pH is close to given pH hence it can act as buffer.
2 points QUESTION 4 Which of the folowing will be the best conjugate acid/base pair to...
Question 11 (2 points) D Which of the following does not represent a conjugate acid-base pair? HCO3/CO32 H3PO4/HPO42 OH/O-2 NH4 /NH3 Save Question 12 (2 points) D Consider the weak acid HCO3 whose pKa -10.32, which form will pre
Question 8 3 pts Which of the following is not a conjugate acid/base pair? O HC2H302/C2H302" O NH4+/NH3 CO2/C03 OH3PO4/H2PO4 Question 9 3 pts A 1.0 M solution of NaC2H3O2 in water is expected to be: Acidic because sodium acetate undergoes hydrolysis Neutral because sodium acetate is a salt Basic because acetate ion is the conjugate base of acetic acid Acidic because it forms acetic acid Question 10 3 pts Examples of ionizing radiation would include: infrared (IR) visible light...
QUESTION 11 Which of the following acid/base conjugate pairs could you use to make a buffer solution with a pH of 2.10? The Kfor the acids are given in parentheses. Chlorous acid / chlorite (Ka = 1.1 10-2) Benzoic acid / benzoate (K, -6.3 * 10-5) O Hydrofluoric acid / fluoride (Ka = 6.6 x 10-4) Hydrogen phosphate / phosphate (Kg = 4.2 x 10-13) Ammonium / ammonia (K, -5.8 * 10-10)
Design a buffer that has a pH of 4.45 using one of the weak base/conjugate acid systems shown below. Weak Base Kb Conjugate Acid Ka pKa CH3NH2 4.2×10-4 CH3NH3+ 2.4×10-11 10.62 C6H15O3N 5.9×10-7 C6H15O3NH+ 1.7×10-8 7.77 C5H5N 1.5×10-9 C5H5NH+ 6.7×10-6 5.17 How many grams of the chloride salt of the conjugate acid must be combined with how many grams of the weak base, to produce 1.00 L of a buffer that is 1.00 M in the weak base? grams chloride...
Design a buffer that has a pH of 4.77 using one of the weak acid/conjugate base systems shown below. Weak Acid Conjugate Base Ka pKa HC2O4- C2O42- 6.4×10-5 4.19 H2PO4- HPO42- 6.2×10-8 7.21 HCO3- CO32- 4.8×10-11 10.32 How many grams of the potassium salt of the weak acid must be combined with how many grams of the potassium salt of its conjugate base, to produce 1.00 L of a buffer that is 1.00 M in the weak base? grams potassium...
a) From the list below, pick an acid, along with its conjugate base, that can be used to make a pH 7.40 buffer. H3PO4 Ka = 6.9 x 10^-3 H2PO4- Ka = 6.4 x 10^-8 HPO42- Ka = 4.8 x 10^-13 b) If you have 0.100 M solutions of the acid and the conjugate base in the system that you picked and there was 20.0 mL of the base, how many mL of the acid would you need to make...
Question 4 (4 points) Match the acid to its conjugate base pair. - CO32- 1. H2CO3 2. HCO3 3. HCI 4. HNO3
10. Assuming equal concentrations of conjugate base and acid, which one of the following mixtures is suitable for making a buffer solution with an optimum pH of 4.6-4.8? A) CHCO02Na / CH3COOH (Ka 1.8 x 10) NH3/NH4CI (K-5.6 x 10-10) в) NaOCl/HOCI (K= 3.2 x 10-) C) NaNO2 / HNO2 (Ka= 4.5 x 104) D) NaCl/HCI E)
Consider how best to prepare one liter of a buffer solution with pH = 3.36 using one of the weak acid/conjugate base systems shown here. Weak Acid Conjugate Base Ka pKa HC2O4- C2O42- 6.4 x 10-5 4.19 H2PO4- HPO42- 6.2 x 10-8 7.21 HCO3- CO32- 4.8 x 10-11 10.32 How many grams of the sodium salt of the weak acid must be combined with how many grams of the sodium salt of its conjugate base, to produce 1.00 L of...
Consider how best to prepare one liter of a buffer solution with pH = 10.93 using one of the weak acid/conjugate base systems shown here. Weak Acid Conjugate Base Ka pKa HC2O4- C2O42- 6.4 x 10-5 4.19 H2PO4- HPO42- 6.2 x 10-8 7.21 HCO3- CO32- 4.8 x 10-11 10.32 How many grams of the sodium salt of the weak acid must be combined with how many grams of the sodium salt of its conjugate base, to produce1.00 L of a...