Question 58 of 68 A diprotic acid, H2A, has Ka1 = 3.4 x 10-4 and Ka2...

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Answer 1

Answer #1

The dissociation of diprotic acid is given by Ka1 H2A Initial H + HA 0.24 Change * Equilibrium 0.24 – x * [H*][HA] _ x.x_=3.4

HA will further dissociates into H+ and A-2 Let y be the change in the conc. of all species at equilibrium. ka2 HA H+ + A 2 I

Answer 2

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