Vapour pressure of Y is 4.050(p1) atm at 290K(T1) and 13.365(p2) atm at 373 K(T2)
We know the equation,
where - gibbs free energy.
R - Universal gas constant (atm) = 8.314J/(mol.K), T - temperature at Kelvin, K - equilibrium constant at pressure. We can substitute pressure itself.
At T = 290K, K = 4.050 atm,
At T = 373K K = 13.365 atm
To find the standard Enthalpy of vaporization, we use the equation,
To find standard entropy, we use the equation,
where delta S is the entropy and T is the temperature.
At 290K, ,
Boiling point = the ratio of standard Enthalpy to standard Entropy.
At 403 K,
From this we calculate vapour pressure using the first equation we used above.
, where R = 8.314 J/K.mol , T = 403 K ,
= - 2.898
= 0.05513
Therefore vapour pressure at 403K is
P = 0.05513 atm
The vapor pressure of Y is 4.050 atm at 290K and 13.365 atm at 373K. What...
The vapor pressure of Y is 4.590 atm at 330K and 9.180 atm at 380K. What are the standard free energies of vaporization at the two temperatures? Hint: vaporization reaction is Y(I) = Y(g). AG330º = kJ/mol AG380º = kJ/mol Assume that the standard entropy and enthalpy of vaporization of Y are independent of temperature and determine their values ASO = J/(mol-K) AH = kJ/mol What is the normal boiling point of Y in degrees Celcius? t = Ос What...
The vapor pressure of Y is 4.560 atm at 440K and 13.680 atm at 515K. What are the standard free energies of vaporization at the two temperatures? Hint: vaporization reaction is Y(l) = Y(g). G440o = -5.55 kJ/mol G515o = -11.20 kJ/mol Assume that the standard entropy and enthalpy of vaporization of Y are independent of temperature and determine their values delta S = J/(mol-K) delta H = kJ/mol What is the normal boiling point of Y in degrees Celcius?...
The vapor pressure of Y is 1.620 atm @ 200K and 4.698 atm @ 273K. What are the standard free energies of vaporization temperatures? Hint: vaporization reaction is Y(l) = Y(g) (at 200K) (at 273K) Assume that the standard entropy and enthalpy of vaporization of Y are independent of temperature and determine their values. (Delta S degrees) (Delta H degrees) What is the normal boiling point of Y in degrees Celcius? t= ? degrees Celsius What is the vapor pressure...
The vapor pressure of Y is 2.320 atm at 420K and 5.336 atm at 478K. What are the standard free energies of vaporization at the two temperatures? Hint: vaporization reaction is Y(u) - Y(9). kJ/mol AG420º = AG478° - kJ/mol Assume that the standard entropy and enthalpy of vaporization of Y are independent of temperature and determine their values 3/(mol-K) AS- AH kJ/mol What is the normal boiling point of Y in degrees Celclus? oc What is the vapor pressure...
The vapor pressure of water is 1.0 atm at 373 K, and the enthalpy of vaporization is 40.7 kJ mol-1 . At what temperature will the vapor pressure be 0.697 atm and at what temperature will the vapor pressure be 1.409 atm?
6.34. The vapor pressure of benzene at 40.0°C is 0.241 atm. If the enthalpy of vaporization of C. Ha is 33.9 kJ/mol, estimate the normal boiling point of benzene.
At what temperature will toluene have a vapor pressure of 517 torr. The normal boiling point of toluene is 110.6C at 1 atm pressure with the molar enthalpy of vaporization being 35.2 kJ/mol
AJ mol Calculate The vapor pressure of water is 1.0 atm at 373 K, and the enthalpy of vaporization is 40 the vapor pressure at 400 K
Two students measured the vapor pressure of water at seven temperatures between 50.0°C and 80.0°C and made a graph of the natural logarithm of the vapor pressure versus the reciprocal temperature. Then the students fit their data to a straight line equation (R2 - 0.997): y = 13.66 - 5076.3x. From this data, calculate the enthalpy of vaporization for water. O a. 114 J/mol .417 J/mol O c. 114 kJ/mol O d.0.417 kJ/mol O e.40.8 kJ/mol O f. 42.2 kJ/mol...
The normal molar vaporization enthalpy (∆H_Vap ^ °) of methanol is worth 37.4 kJmol ^ (- 1), and its normal molar vaporization entropy (∆S_Vap ^ °) 110.9 JK ^ (- 1) mol ^ (- 1). Calculate: The vapor pressure of methanol, at 298 K (R = 8.3144 J K -1 mol -1). The approximate normal boiling point. The boiling point for an external pressure of 0.1 atm. Applying the Clausius-Clapeyron equation, estimate the cooking temperature in a pressure cooker whose...