Question

The vapor pressure of Y is 2.320 atm at 420K and 5.336 atm at 478K. What are the standard free energies of vaporization at the two temperatures? Hint: vaporization reaction is Y(u) - Y(9). kJ/mol AG420º = AG478° - kJ/mol Assume that the standard entropy and enthalpy of vaporization of Y are independent of temperature and determine their values 3/(mol-K) AS- AH kJ/mol What is the normal boiling point of Y in degrees Celclus? oc What is the vapor pressure of Y at 508 K? atm

Answer 1

Prees Solution As we know AG; = - RT enk for reaction Y C) = yeg) → AGA = -Rten (pros? I at T = 420k , Pug = 2.320 atm = AG = - 8.314J X 420 kxen 12:32) molik 3 - 2.94 x 10" The = [-2.94/KIR And at T=478K , Pria = 5.336 atm 36 A Gize = = - 8.314 I __ X 478 K x en molik 6065 x 103 J - mol 16.65 KI mol