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The vapor pressure of Y is 4.590 atm at 330K and 9.180 atm at 380K. What...
The vapor pressure of Y is 4.050 atm at 290K and 13.365 atm at 373K. What are the standard free energies of vaporization at the two temperatures? Hint: vaporization reaction is Y(I) = Y(g). «J/mol AG290º = AG373° = kJ/mol Assume that the standard entropy and enthalpy of vaporization of Y are independent of temperature and determine their values J/(mol-K) AS° = AH° = kJ/mol What is the normal boiling point of Y in degrees Celcius? 1 t= t =...
The vapor pressure of Y is 4.560 atm at 440K and 13.680 atm at 515K. What are the standard free energies of vaporization at the two temperatures? Hint: vaporization reaction is Y(l) = Y(g). G440o = -5.55 kJ/mol G515o = -11.20 kJ/mol Assume that the standard entropy and enthalpy of vaporization of Y are independent of temperature and determine their values delta S = J/(mol-K) delta H = kJ/mol What is the normal boiling point of Y in degrees Celcius?...
The vapor pressure of Y is 1.620 atm @ 200K and 4.698 atm @ 273K. What are the standard free energies of vaporization temperatures? Hint: vaporization reaction is Y(l) = Y(g) (at 200K) (at 273K) Assume that the standard entropy and enthalpy of vaporization of Y are independent of temperature and determine their values. (Delta S degrees) (Delta H degrees) What is the normal boiling point of Y in degrees Celcius? t= ? degrees Celsius What is the vapor pressure...
The vapor pressure of Y is 2.320 atm at 420K and 5.336 atm at 478K. What are the standard free energies of vaporization at the two temperatures? Hint: vaporization reaction is Y(u) - Y(9). kJ/mol AG420º = AG478° - kJ/mol Assume that the standard entropy and enthalpy of vaporization of Y are independent of temperature and determine their values 3/(mol-K) AS- AH kJ/mol What is the normal boiling point of Y in degrees Celclus? oc What is the vapor pressure...
The vapor pressure of water is 1.0 atm at 373 K, and the enthalpy of vaporization is 40.7 kJ mol-1 . At what temperature will the vapor pressure be 0.697 atm and at what temperature will the vapor pressure be 1.409 atm?
At 330 K the vapor pressure of pure n-pentane is 1.92 atm and the vapor pressure of pure n-octane is 0.07 atm. If 330K is the normal boiling point for a solution of these two substances, what will the mole fractions of each substance be in that solution? [If you can't figure out how to do this mathematically, you can estimate from the plot..... for reduced credit.] Octane+Pentane Pvaps at 330K po Pentane P (atm) Ptot Pv Pent Pv Oct...
6.34. The vapor pressure of benzene at 40.0°C is 0.241 atm. If the enthalpy of vaporization of C. Ha is 33.9 kJ/mol, estimate the normal boiling point of benzene.
At what temperature will toluene have a vapor pressure of 517 torr. The normal boiling point of toluene is 110.6C at 1 atm pressure with the molar enthalpy of vaporization being 35.2 kJ/mol
AJ mol Calculate The vapor pressure of water is 1.0 atm at 373 K, and the enthalpy of vaporization is 40 the vapor pressure at 400 K
- O ADVANCED MATERIAL Calculating vapor pressure from boiling point and enthalpy of va... KJ The enthalpy of vaporization of Substance X is 9.00 – and its normal boiling point is -104. °C. Calculate the vapor pressure of X at -172. °C. mol and its Round your answer to 2 significant digits. atm x 6 ?