The vapor pressure of water is 1.0 atm at 373 K, and the enthalpy of vaporization is 40.7 kJ mol-1 . At what temperature will the vapor pressure be 0.697 atm and at what temperature will the vapor pressure be 1.409 atm?
The vapor pressure of water is 1.0 atm at 373 K, and the enthalpy of vaporization...
AJ mol Calculate The vapor pressure of water is 1.0 atm at 373 K, and the enthalpy of vaporization is 40 the vapor pressure at 400 K
Can you show the work for these problems? Ethanol has an enthalpy of vaporization of 42.3 kJ/mol. The compound has a vapor pressure of 1.00 atm at 78.3 degree C. At what temperature is the vapor pressure equal to 0.800 atm? (R = 8.314 J/K middot mol) -83.8 degree C -24.4 degree C 62.6 degree C 73.0 degree C 78.0 degree C A liquid has an enthalpy of vaporization of 30.4 kJ/mol. At 269 K is has a vapor pressure...
The vapor pressure of Y is 4.590 atm at 330K and 9.180 atm at 380K. What are the standard free energies of vaporization at the two temperatures? Hint: vaporization reaction is Y(I) = Y(g). AG330º = kJ/mol AG380º = kJ/mol Assume that the standard entropy and enthalpy of vaporization of Y are independent of temperature and determine their values ASO = J/(mol-K) AH = kJ/mol What is the normal boiling point of Y in degrees Celcius? t = Ос What...
The vapor pressure of Y is 2.320 atm at 420K and 5.336 atm at 478K. What are the standard free energies of vaporization at the two temperatures? Hint: vaporization reaction is Y(u) - Y(9). kJ/mol AG420º = AG478° - kJ/mol Assume that the standard entropy and enthalpy of vaporization of Y are independent of temperature and determine their values 3/(mol-K) AS- AH kJ/mol What is the normal boiling point of Y in degrees Celclus? oc What is the vapor pressure...
The vapor pressure of Y is 4.050 atm at 290K and 13.365 atm at 373K. What are the standard free energies of vaporization at the two temperatures? Hint: vaporization reaction is Y(I) = Y(g). «J/mol AG290º = AG373° = kJ/mol Assume that the standard entropy and enthalpy of vaporization of Y are independent of temperature and determine their values J/(mol-K) AS° = AH° = kJ/mol What is the normal boiling point of Y in degrees Celcius? 1 t= t =...
The vapor pressure of Y is 4.560 atm at 440K and 13.680 atm at 515K. What are the standard free energies of vaporization at the two temperatures? Hint: vaporization reaction is Y(l) = Y(g). G440o = -5.55 kJ/mol G515o = -11.20 kJ/mol Assume that the standard entropy and enthalpy of vaporization of Y are independent of temperature and determine their values delta S = J/(mol-K) delta H = kJ/mol What is the normal boiling point of Y in degrees Celcius?...
6.34. The vapor pressure of benzene at 40.0°C is 0.241 atm. If the enthalpy of vaporization of C. Ha is 33.9 kJ/mol, estimate the normal boiling point of benzene.
31.- The molar heat capacity of water vapor at a constant pressure of 1.0 atm is represented by Op = 30.54 J K-mol-+ (0.01029 J K-2 mol-'T where T is the Kelvin temperature. Find the amount of heat required to raise the temperature at constant pressure of 2.0 mol of water vapor from 100.0°C to 500.0°C. (A) 9.35 kJ (B) 29.15 kJ (C) 42.12 kJ (D) 13.98 kJ (E) 55.81 kJ OM (B О О О О О C (E
The heat of vaporization of water at 373 K is 40.7 kJ/mol Part A Find for the evaporation of 471 g of water at this temperature. Express your answer with the appropriate units. HAO ? 9= 999 Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Find to for the evaporation of 471 g of water at this temperature. Express your answer with the appropriate units.
The vapor pressure of Y is 1.620 atm @ 200K and 4.698 atm @ 273K. What are the standard free energies of vaporization temperatures? Hint: vaporization reaction is Y(l) = Y(g) (at 200K) (at 273K) Assume that the standard entropy and enthalpy of vaporization of Y are independent of temperature and determine their values. (Delta S degrees) (Delta H degrees) What is the normal boiling point of Y in degrees Celcius? t= ? degrees Celsius What is the vapor pressure...