Question

4,

The 750 mL bottle of Lindeman's Shiraz wine in my kitchen is 7.75 % ethanol by volume. The density of ethanol is 0.789 g/mL. What is the molarity of the wine with respect to the solute ethanol?

5.

To make a saturated aqueous solution of ammonia, 470 g of ammonia are dissolved with one liter of water. The density of the resulting solution is 0.89 g/mL. What is the molarity of the solution? Hint: Think about the two quantities you need to calculate the molarity of a solution, then figure out how to get those two quantities from the information supplied in the problem, so that you can calculate the molarity.
6.

You found a 1 pound (454 g) container of drain cleaner, mostly solid sodium hydroxide, that you wish to neutralize by reacting it with vinegar. The vinegar is a 5% solution of acetic acid (meaning that 100 g of vinegar would contain 5 g of acetic acid) and the vinegar has a density of 1 g/mL. How many liters of vinegar will it take to just neutralize the drain opener?

7.

In the "Precipitate Formed" columns of the table below write the formula of the compound formed as a precipitate when the "Solution A" compound is mixed with the "Solution B" compound in the same row (working left to right). In this case, and for good practice, be sure to include the (s) notation immediately after the chemical formula with no space between. If no precipitate is expected to form, write the word "none" (no quotes!) in the ChemPad box.

Solution A	Solution B	Precipitate Formed	Solution A	Solution B	Precipitate Formed
KNO3(aq)	BaCl2(aq)		Ba(NO3)2(aq)	NaCl(aq)	chemPad ​​​​​​​
Na2SO4(aq)	Pb(NO3)2(aq)		Na2S(aq)	Cu(NO3)2(aq)	​​​​​​​
KOH(aq)	Fe(NO3)3(aq)		NH4Cl(aq)	Pb(NO3)2(aq)	​​​​​​​

Answer 1

kindly post different questions separately. please rate

present 4 7.75 1. ethanol by volume means 7.75 mL of ethanol is in 100 ml of wine In 100 ml of wine, volume of ethanal = 7.75 mL In 750 mL of wine, volume of ethanol = 7.75 mL X 750 mL 100mL 58.12.5 ML density of ethanol = 0.789 gimL man of ethand - density x volume = 0.789 gim L x 58.125 ml = volume of wine = 750ml = 0.750 L 1:1000mL=1L) 45.86 2 molar man ethanol = 46.07 g/mol moles of ethanol = = mass molarmas 0.995 mol = 45.869 46.0791mol molarity of wine – moles of ethanol Volume of wine linhl = 0.995 mol 0.750 L = 1.33 M Answer