H3PO4 (aq) + 3NaOH (aq) → Na3PO4 (aq) + 3H2O (l)
2H2 (g) + S2 (g) → 2H2S(g)
N2 (g) + 3H2 (g) → 2NH3 (g)
3)
volume % = 11.0 %
volume % = (volume of ethanol / total volume) x 100
11.0 = (volume of ethanol / 750 ) x 100
volume of ethanol = 82.5 mL
4)
mass of sucorse = 100 g
moles of sucrose = 100 / 342 = 0.292
Molarity = 0.292 / 0.500 = 0.585
Molarity = 0.585 M
5)
250 x 0.100 = 0.585 x V
V = 42.7 mL
volume of concentrated solution = 42.7 mL
6)
H3PO4 (aq) + 3NaOH (aq) → Na3PO4 (aq) + 3H2O (l)
mmoles of NaOH = 25.0 x 0.100 = 2.5
mmoles of H3PO4 = 2.5 / 3 = 0.833
0.250 x V = 0.833
V = 3.33
voume of H3PO4 = 3.33 mL
7)
2H2 (g) + S2 (g) → 2H2S(g)
Kc = [H2S]2 / [H2]2[S2]
= (1.25)^2/ (0.100)^2(0.500)
Kc= 312.5
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