Question

Question 6 of 11 Sub The solubility of Ag2SO4 in water at 25 °C is 0.0155 M. What is Ksp for Ag2SO4? * 1 2 3 C | 7 8 9 +/- X 100

Answer 1

Ans :-

Let solubility of Ag₂SO₄ = S mol/L = 0.0155 M (Given)

Partial dissociation of sparingly soluble salt Ag₂SO₄ is :

Ag₂SO₄ (s) <------------------------> 2Ag⁺ (aq) ..................+.....................SO₄^2- (aq)

.........................................................2S mol/L..............................................S mol/L

Expression of Solubility product (K_sp) which is equal to the product of the molar concentration of products raise to the power of stoichiometric coefficient at equilibrium stage of the reaction.

K_sp = [Ag⁺]².[SO₄^2-]

= (2S)².(S)

= (2 x 0.0155 M)².(0.0155 M)

= 1.49 x 10^-5 M³

Therefore, K_sp of Ag₂SO₄ = 1.49 x 10^-5 M³