Part B A 457-mL sample of unknown HCl solution reacts completely with Na,COto form 11.1 g...

Question

Question

Answer 1

Answer #1

According to question chemical balanced equation

2HCl + NaCO3 + C02 + H2O+2NaCl

Given mass of CO₂ (m)= 11.1 g

Molar mass of CO₂ (M) = 44 g/mol

Numberofmoles(n)) = 11.19 449/mol

n = 0.25227mol

From the equation, 2 ratio 1 between HCl and CO₂

1 mol CO₂ = 0.25227 mol

1molHCl = 2 * 0.25227mol = 0.50454mol

22 Concentration == Volume

Volume = 457 mL = 0.457 L

0.50454mol HCl) = * = 1.10402mol/L 0.457L

HCl = 1.11M

Answer 2

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