The reaction 2 H202 + 2H2O + O2 has the following mechanism: H2021H2010 H2O2 +10 H2O...
i. For the reaction: 2H202→ 2H2O+O2 a proposed mechanism is: H2O2 + H3O2+ → H2O + H30+ +02 (a) The intermediate in the proposed mechanism is The catalyst is (b) Apply the steady state approximation to this mechanism to deduce the rate law in terms of d[O2]/dt. (15 pts)
8. The rate law for the reaction H2O2 + 2H+212 + 2H2O is rate-k[H202][1]. The following mechanism has been suggested. H2O2+1 - HOI + OH - slow OH + H H20 fast HỘI + H+ + + I2 + H2O fast Identify all intermediates included in this mechanism. A) H and I D) Honly B) H and HOI E) H20 and OH C) HOI and OH 9. Which of the following statements is false? A) A catalyst increases the rate...
The elementary reaction 2H2O(g)−⇀↽−2H2(g)+O2(g)2H2O(g)↽−−⇀2H2(g)+O2(g) proceeds at a certain temperature until the partial pressures of H2O,H2O, H2,H2, and O2O2 reach 0.0200 atm,0.0200 atm, 0.00550 atm,0.00550 atm, and 0.00700 atm,0.00700 atm, respectively. What is the value of the equilibrium constant at this temperature? kp= ?
1- The equilibrium constant, Kc, for the following reaction is 1.80×10-2 at 698 K. 2HI(g) --------> H2(g) + I2(g) Calculate the equilibrium concentrations of reactant and products when 0.395 moles of HI are introduced into a 1.00 L vessel at 698 K. [HI] = M [H2] = M [I2] = M 2- student ran the following reaction in the laboratory at 1090 K: 2SO3(g) ----------> 2SO2(g) + O2(g) When he introduced SO3(g) at a pressure of 1.05 atm into a 1.00...
The reaction 2H2O2(aq)→2H2O(l)+O2(g) is first order in H2O2 and under certain conditions has a rate constant of 0.00752 s−1 at 20.0 ∘C. A reaction vessel initially contains 150.0 mL of 30.0% H2O2 by mass solution (the density of the solution is 1.11 g/mL). The gaseous oxygen is collected over water at 20.0 ∘C as it forms. What volume of O2 will form in 73.9 seconds at a barometric pressure of 719.5 mmHg . (The vapor pressure of water at this...
Under which of the following initial conditions would the reaction 2 H2O2(l) 2 H2O(l) + O2(g) NOT be able to acheive equilibrium? a. H2O2(l) is added to the flask. b. H2O2(l) and H2O(l) are added to the flask. c. H2O2(l) and O2(g) at a pressure larger than Kp are added to the flask. d. They can all achieve equilibrium.
(1). The equilibrium constant, Kp, for the following reaction is 1.80×10-2 at 698K. 2HI(g) =H2(g) + I2(g) If an equilibrium mixture of the three gases in a 15.5 L container at 698K contains HI at a pressure of 0.399 atm and H2 at a pressure of 0.562 atm, the equilibrium partial pressure of I2 is atm. (2). Consider the following reaction: PCl5(g) =PCl3(g) + Cl2(g) If 1.17×10-3 moles of PCl5, 0.217 moles of PCl3, and 0.351 moles of Cl2 are at...
The equilibrium constant, Kp, for the following reaction is 1.80x10-2 at 698K. 2HI(g) =H2(g) +12(g) If an equilibrium mixture of the three gases in a 14.3 L container at 698K contains HI at a pressure of 1.09 atm and H, at a pressure of 0.929 atm, the equilibrium partial pressure of I, is atm. Submit Answer Retry Entire Group 9 more group attempts remaining
The elementary reaction 2H2O(g)−⇀↽−2H2(g)+O2(g) proceeds at a certain temperature until the partial pressures of H2O, H2, and O2 reach 0.0750 atm, 0.00850 atm, and 0.00650 atm, respectively. What is the value of the equilibrium constant at this temperature?
For the reaction O2 (g) + 2F2 (g) ⇌ 2OF2 (g), Kp = 41.0. If the partial pressure of O2 is 0.116 atm and the partial pressure of F2 is 0.0461 atm at equilibrium, what is the pressure of OF2 at equilibrium?