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In a coffee cup calorimeter, 100.0 mL of 1.00 M NaOH and 200.0 mL of 0.80...

In a coffee cup calorimeter, 100.0 mL of 1.00 M NaOH and 200.0 mL of 0.80 M HCl are mixed at 25.0oC. After the reaction, the temperature is 29.5 oC. Assuming all solutions have a density of 1.00 g/cm3 and a specific heat capacity of 4.18 J/oC g, what is the enthalpy change (kJ) for the balanced reaction?

HCl(aq) + NaOH(aq)  => NaCl(aq) + H2O(l)

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Answer #1

Answer 100 ml of 1.004 NaoH 20ome of 0.8m Ho Total volume = 800 mL = 300 cm3 . denstly = 1 g/cm3 mass= 300 g T = 256 T2 = 29

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