Question

please answer both.

1. The following represents the structure of the various transition metal complexes accurately drawn with necessary geometry. In the spaces provided a. Show the electron counting b. Oxidation state of the metal center and ligand charges if present (You don't have to draw out phenyl rings on ligands (e.g., for PPh3))

Answer 1

Electron counting =Velence electron of metal+Electron donate by ligand +- Charge on sphere

In Re structure velence electron are 7.here 8 electron donate by two dppe ligand, two electron by ethene, One electron by chlorine.

Electron counting =7+8+2+1-1positive charge

=17

Oxidation state of metal = +2

one +charge on sphere and +1 charge induce by negative charge chlorine

(2).Velence electron in Au=11

2 electron by two ph as ligand each by one

2 electron by Iodine as ligand each by one.

Total Electron counting=

11+2+2+(1negative charge)=16

Oxidation state of metal =

(x+4)= -1

x= -5

Where X is oxidation state of Au

in above equation +4 was charge created on metal by four negative charged ligand

-1 is charge on sphere.