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Below is a Eh-pH diagram for sulfur species (at 25C, 1bar). What is the stable species at Eh = 0.5 V and pH = 7? 1.0 HSO; SO-
In acid mine drainage, oxidation of exposed pyrite leads to the leaching of sulfuric acid (HSO4) in the effluent. By looking
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Answer #1

HSO; Intersection Point SO- His -0.5 HS 0 4 6 8 10 12 14

In the above diagram

step 1- draw a line parallel to Y-axis from X-axis starting from pH=7

step 2- draw another line parallel to X-axis from Y-axis starting from Eh=0.5

the point where both lines intersect is the region of SO42-

So, at Eh = 0.5 & pH= 7, the stable specie will be SO42-

part 2-

We can clearly see that in Eh/pH diagram

at lower pH HSO4- is Stable

if we Increase pH then HSO4- will be converted into SO42-

& Increasing pH means Increasing Alkalinity

From here we can conclude that

by increasing pH & by increasing Alkalinity

we can get rid of HSO4-.

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