Question

Please help with this problem

Gaseous indium dihydride is formed from the elements at elevated temperature: In(g) + H2(g) = InH2(g), K = 1.48 at 973 K Part A The partial pressures measured in a reaction vessel are P = 0.0500atm PH = 0.0310atm POH = 0.0740atm Calculate Qp Express the reaction quotient to three significant figures. VO AE O aj ? Qp- Submit Request Answer Part B Specify the direction of reaction to attain equilibrium The reaction will proceed in the reverse direction to attain equilibrium The reaction will proceed in the forward direction to attain equilibrium Submit Request Answer

Answer 1

In(g) + H2(g) ---------> InH2(g)
Qp = (PINH2)/(PIn)(PH2)
    = 0.074/(0.05*0.031)
    = 47.7 >>>>answer
part-B
Kp = 1.48
Qp = 47.7
Qp>Kp The equilibrium shift to reverse direction
The reaction will proceed in the reverse direction to attain equilibrium>>>>answer
part-C
------ In(g) + H2(g) ---------> InH2(g)
I ----- 0.05---0.031-----------0.074
C------ +x ----- +x -------------x
E----- 0.05+x --- 0.031+x ------ 0.074-x
   Kp   = (PINH2)/(PIn)(PH2)
   1.48 = (0.074-x)/(0.05+x)(0.031+x)
   1.48(0.05+x)(0.031+x) = (0.074-x)
     x = 0.059
PIn = 0.05 + x = 0.05+0.059   = 0.109atm
part_D
PH2 = 0.031+x = 0.031+0.059   = 0.0900atm
part-E
PInH2 = 0.074-x = 0.074-0.059 = 0.0150atm