Question

o prase Ul Water to 2. What is the heat, q, required to melt 10 grams of ice in a) Joules b) calories? 122.3 °C). The goC. Assuming -4.18 /(8°C) 3. A piece of metal weighing 49.047 g was heated to 100.0 °C and then put it into 100.0 m water initially at 22.3 °C). The metal and water were allowed to come to an equilibu temperature, determined to be 27.8 °C. Assuming no heat lost to the environment, calculat specific heat of the metal. Specific heat of water = 4.18 J/(g.°C)

Answer 1

2.) ohr of water = 3345/g 9 required to melt logice = 339X10 = 3340 J in in calor caloriess 0,239 X 3340 = 798.28 calories. - 3.) let specific heat of metal es con so heat release be metal = heat absorb by waben 49.047 x cm x (100-27.8) = 100x 4-18* (27.8-22-3) cm = 0.6492 J/g °c ( specific heat of metal)

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