Question

Experiment 10 Pre laboratory Problems Name 1. What type of compound or element ionic, metallic or covalent) are the following: a b. c. d. e. f. Glass Graphite in pencil lead Aluminum Copper Solid Naci Naco 8. HCI h. (NH4)2SO4 | || H4)2 j. CH2021 k CH OH 1. Agcl 2. What is the net ionic equation of solid Na Cos dissolving in water? a. Explain how you can quickly differentiate between electrolytes and nonelectrolytes?

Answer 1

Ans 1)

(a) Glass - Covalent

(b) Graphitein pencil lead - Covalent

(c) Aluminium - Metallic

(d) Copper - Metallic

(e) Solid NaCl - Ionic

(f) Na2CO3 - Ionic

(g) HCl - ionic

(h) (NH4)2SO4 - Ionic

(i) HC2H3O2 - Covalent

(j) C12H22O11 - Covalent

(k) C2H5OH - Ionic

(l) AgCl - Ionic

Ans 2)

Sodium carbonate reacts with water to produce sodium bicarbonate and sodium hydroxide.

Na2CO3 + H2O $\rightarrow$ NaHCO3 + NaOH

(a)

Electrolytes are molecules that ionize completely in solution. So, electrolyes solution conduct electricity.

Nonelectrolytes do not dissociate into ions in solution. So, nonelectrolyte solutions do not conduct electricity.

Ans 3)

A strong electrolyte (SE) is a solution/solute that completely, or almost completely, ionizes or into solution.

A weak electrolyte (WE) does not completely dissociate in aqueous solution.

A nonelectrolyte (NE) is a substance that does not dissociate in an aqueous medium.

(a) Glass - Non conductor

(b) Graphitein pencil lead- Conductor

(c) Aluminium - Conductor

(d) Copper - Conductor

(e) Solid NaCl - SE

(f) 0.1 M Na2CO3 - SE

(g) 0.1 M HCl - SE

(h) 0.1 M (NH4)2SO4 -SE

(i) 0.1 M HC2H3O2 - WE

(j) 0.1 M C12H22O11 - NE

(k) C2H5OH - WE

(l) 0.1 M AgCl - SE