E0cell= E0red-E0oxd
Oxidation (Anode) : P H3PO4 -0.411
Reduction (Cathode) : NO3- NO +0.957
3 P + 5 HNO3 + 2 H2O 5 NO + 3 H3PO4
3 P(0) - 15 e- 3 P (V) Oxidation
5 N(V) +15 e- 5 N(II) Reduction
E0cell= E0red-E0oxd = 5 x0.957 – 3(-0.411) = 4.785 + 1.233 = 6.018 V
Answer is 6.02 V
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GlauUUUUR URION Downloadable eTextbook signment FULL SCREEN PRI ES Chapter 17, Question 27 Parameterization Calculate Eº...
Use standard reduction potentials to calculate ΔG° for the reaction: 3 P + 5 HNO3 + 2 H2O →5 NO + 3 H3PO4 E°H3PO4/P, H3O+ = -0.411, E°NO3-/NO, H3O+ = +0.957. (answer in kj) The number of significant digits is set to 3; the tolerance is +/-1.0%
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