Question

For cases where [A] exactly doubles: • if the rate does not change, the order for A is 0. • if the rate doubles, then the order for A is 1. . if the rate quadruples, the order for A is 2. For more complex cases, use the general equation: ratei reactant), order rate, reactant), What is the reaction order with respect to A? [A], mol/L 0.250 0.500 0.250 0.645 [B], mol/L 0.220 0.220 Trial 1 Trial 2 Trial 3 Trial 4 rate, mol/(L-min) 0.0317 0.0635 0.0635 0.124 0.440 0.332 Rate = k[A]orderA[BjorderB .0625

Answer 1

The given rule for the determination of order of reaction is applicable when concentration of one specie is changed while that of others are kept constant.

From trial 1and 2, concentration of B is kept constant.While,on doubling the concentration of A the rate becomes double.It implies that the order is 1 with respect to A.

Simlarly from trial 1 and 3,we found the order with respect to B is 1.

Therefore complete order of the reaction will be 2. (Sum of order of all reactant).