Question

Attempt 13 estion 11 of 14 > Calculate the Hand pH of a 0.0050 M hydrofluoric acid solution. The K, of hydrofluoric acid is 6

I cant figure out H+
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Answer #1

e given that, [hf] = 0.005 ka = 6.80x104 Solution - Htcaq) + fcaq) HF (aq) 0.005 - C til out (0.005-x) UUUUU Ka (H+] [F] [hf]

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