Calculate the [H+] and pH of a 2.29×10−4 M hydrofluoric acid solution. The ?a of hydrofluoric acid is 6.80×10−5
Calculate the [H+] and pH of a 2.29×10−4 M hydrofluoric acid solution. The ?a of hydrofluoric...
Calculate the pH of a solution that is 0.100 M in hydrofluoric acid (HF) and 0.100 M in sodium fluoride (NaF). Ka of hydrofluoric acid is 6.3 x 10-4
4. Calculate the pH of a buffer solution made from 0.30 M hydrofluoric acid and 0.70 M sodium fluoride after the addition of 0.04 mol of HCl to 1 L of this solution. Assume no change in volume. K.-7.1x10+ 5. Calculate the pH of a 0.04 M HCl solution. Compare to the pH found in problem 4 Note: this is not a buffer! 6. What properties of a buffer solution provides for a solution with a higher capacity to withstand...
0.80 X 10 . Use the Calculate the [H] and pH of a 0.0045 M hydrofluoric acid solution. The method of successive approximations in your calculations for a 0.0015 Mb TH) pH If the Ks of a weak base is 6.7 x 10-, what is the pH of a 0.16 M solution of this base? pH- of a weak base has a pH of 9.60. What is the base hydrolysis constant, Ks, for the weak base?
0.80 X 10 . Use the Calculate the [H] and pH of a 0.0045 M hydrofluoric acid solution. The method of successive approximations in your calculations for a 0.0015 Mb TH) pH If the Ks of a weak base is 6.7 x 10-, what is the pH of a 0.16 M solution of this base? pH- of a weak base has a pH of 9.60. What is the base hydrolysis constant, Ks, for the weak base?
4. Calculate the pH of a solution that is 0.98 molar hydrofluoric acid (5) Ka (HF) = 6.8 x 10-4 Fill in the ICE table, (H1+), and pH.
I cant figure out H+
Attempt 13 estion 11 of 14 > Calculate the Hand pH of a 0.0050 M hydrofluoric acid solution. The K, of hydrofluoric acid is 6.80 x 10 . Use the method of successive approximations in your calculations. H'] 1.84 X10-3 pH = 2.735
Calculate the (H+) and pH of a 2.37 x 10-4 M iodoacetic acid solution. The K, of iodoacetic acid is 6.68 x 10-5. [H+) = M pH =
Calculate the [H+) and pH of a 3.75 x 10-4 M butanoic acid solution. The K, of butanoic acid is 1.52 x 10-5. M pH =
Calculate the [H+] and pH of a 1.23 x 10-4 M nitrous acid solution. The K, of nitrous acid is 7.10 x 10-5. [H+] = 1.4 X10-4 pH = 3.9
If a solution of HF (Ka=6.8×10^−4) has a pH of 3.50, calculate the concentration of hydrofluoric acid. So far, I've made 5 incorrect attempts at the answer and have one attempt remaining. My answers were as follows: 0.00015, 1.5x10^-4, 1.5x10^-5, 0.001, and 0.00032 (This last answer prompted the website to tell me: "This value is the concentration of H+. This concentration and the Ka value can be used along with the equation for Ka to determine the initial concentration of...