Question

Consider the following system at equilibrium where AH° = 16.1 kJ, and K. -6.50x10. at 298 K. 2NOBr(g) = 2NO(g) + Brz(9) If the VOLUME of the equilibrium system is suddenly decreased at constant temperature: The value of K. A. increases. B. decreases. C. remains the same. The value of QcL A . is greater than Kc. B. is equal to Ke C. is less than Ka The reaction must: A. run in the forward direction to reestablish equilibrium. B. run in the reverse direction to reestablish equilibrium. C. remain the same. It is already at equilibrium. The number of moles of Br2 will: A. increase. B. decrease. C. remain the same. Submit Answer Retry Entire Group 6 more group attempts remaining

Answer 1

--> value of Kc does not depend on volume so, it will remain constant.

--> As there are more mole of product so decrease in volume will shift reaction to the side with the fewer moles that is reactant side. It means it will shift backward. Hence Qc >Kc.

--> reaction must run in the reverse direction to regain the equilibrium.

--> moles of Br2 will decrease as reaction is going in the reverse direction.

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