Question

= 0.159, at 723 K. Consider the following system at equilibrium where AH = -111 kJ, and K N2(g) + 3H2(g) 2NH3(g) If the VOLUME of the equilibrium system is suddenly decreased at constant temperature: The value of KO A. increases. B. decreases. C. remains the same. The value of Qc A. is greater than K B. is equal to Kc C. is less than Kc The reaction must: A. run in the forward direction to reestablish equilibrium. B. run in the reverse direction to reestablish equilibrium. C. remain the same. It is already at equilibrium. The number of moles of Hy will: A. increase. B. decrease C. remain the same. Submit Answer Submit Answer Retry Entire Group 6 more group attempts remaining

Answer 1

N2 + 3H₂ ² 2 Nola Ang = = -2 (-ve) (2) - Product (3+1) Reactant If Volume is decreased than Pressure increased - Value of kc [] Remain same changing by Pressures {kc is not - Value of ac [U is less than ke to Product sich Because equilibrium shift I when Pressure increased -> The Reaction must A7 Run in forward direction to reestablishe {quilibrium - The ho. of mole of H₂ will I B decrease (Because when reaction run direction Reactant convert So molc H2 consume in for ward ? in to product