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What mass (g) of CaF 2 is formed when 30.4 mL of 0.438 M NaF is...

What mass (g) of CaF 2 is formed when 30.4 mL of 0.438 M NaF is treated with an excess of aqueous calcium nitrate?

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Ca(NO₃). + 2 NaF - CaF₂ + 2 Na NO₂ NaF is the limiting neagent. I mol of Ca(NO₃). neacts with 2 mol of NaF and prooduces i mo

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