2. A compound containin ng uranium and fluorine weighed 1.760 grams and was treated with excess...

Question

Question

Answer 1

Answer #1

The weight of CaF₂ = 1.17 gm

Moles of CaF₂ = 1.17 / 78.07 = 0.01498 Moles

Moles of Florine presents = 0.0299 Moles

Weight of Fluorine = 0.0299 x 18.99 = 0.5694 gm

% of Fluorine in the sample = 0.5694 x 100 /1.76 = 32.35 %

Answer 2

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