Question

Question 2 (4 points) In the following Haworth structure, is this the A or B anomer? CH,OH OH OH H O a, because the OH is below the plane of the ring OB, because the OH is below the plane of the ring a, because the OH is above the plane of the ring OB, because the OH is above the plane of the ring

Answer 1

solution ? choueture z glucose is CHO H -c-oh A tooth HoH + oH H toh HO- - H HOA -c-oH -CH₂OH CHOH D(+) glucose.

Date Page. glucose LH 0– – H Cyclic structure of 애 T 01 DET 와애 i | 라에 = 애 여 개와애 7 방그와 한해 X-D-(+)-glucose B-D-(+)- glocose A. LN NOH- 9 아 12 OH X-D-(+) = gtacopyrattose here, oh in C is below the toneeton-2 plane of ring ㅐ해 B-D-(+)-glucopyɣanose. here of in the plane of ring. 6래에 0 A HH it is a anomer. og herause the of (in c,) is below The plane of the ring .

ro Page Fischer projection :- TC? HOVH Hoy tho SCHOH is used 5 number carbor determine whether to the sugar is D or 27 It the hydroxyl group on is to the right side of me the sugar is D- ugar. me 5th molecule carbon men It me hydroxyl tott) group on me 5th carbon (Cs) is to me left side of me molecule hen me sugur is L- sugar . Above sugar is L-sugar..