see experiment 1 and 3:
[A] doubles
[B] is constant
rate becomes 4 times
so, order of A is 2
see experiment 1 and 2:
[A] is constant
[B] doubles
rate is constant
so, order of B is 0
Rate law is:
rate = k*[A]^2
Put values from 1st row of table in rate law
rate = k*[A]^2
1.12*10^-2 = k*0.34^2
k = 0.0969 M-1.s-1
Answer: 0.0969 M-1.s-1
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