Question

A student sets up the following equation to convert a measurement. (The ? stands for a number the student is going to calculate.) Fill in the missing part of this equation. Note: your answer should be in the form of one or more fractions multiplied together. (14. a'm"). () = ? Pam x $ ?

Answer 1

The given equation for the conversion is, de 14 Pa.cms = ? kpa. m For the above conversion first we have to observe the relation between Pascal(a) and kilo pascal (kpa). - 1 kipa = 10 pa. A pa= 108kpa similarly, the relation between m3 and cm3 is. 1. Comb = 1 (10cm) = 100cm (= Im=ločom) 1m3 - 106 cm3 - 1 cm = 100 ml Now the above relations should be Substituted in the given equation 14.(Pa)(cm) = 14 (182kPa) (15mm) = (14)(10%)(169) Kpams = 14x109 kpam3 - [14 Pacemº)- 14x17% kParma (1. Ra.com). 109 = 14 KPuma ?