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QUESTION 26 In the following, what was reduced? Zn + 2HBr --> ZnBr2 + H2 O H2 Zn in ZnBr2 OH in HBO o Zn Br in ZnBr2
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uz. eatet t zeu uz + 7H 1 ozidation no. - of zn=o ozidation no. . of H=t1 ouidtion no. of zn=+2 ouidation no. of t=0 - thin H

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QUESTION 26 In the following, what was reduced? Zn + 2HBr --> ZnBr2 + H2 O...
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