Given that the initial rate constant is 0.0160s-1 at an initial temperature of 24 deg C, what would the rate constant be at a temperature of 100 deg C for the same reaction described in Part A?
From Part A:
The activation energy of a certain reaction is 31.5 kJ/mol. At 24∘C, the rate constant is 0.0160s−1. T2 = 41C
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Given that the initial rate constant is 0.0160s-1 at
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The activation energy of a certain reaction is 37.3 kJ/mol . At 20 °C, the rate constant is 0.0120s-. At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units. View Available Hint(s) μΑ Submit Previous Answers Part B Given that the initial rate constant is 0.0120s at an initial temperature of 20 °C, what would the rate constant be at a temperature of 120. °C for...
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