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This is a Lewis structure example on my Chemestry book. But I am very confused about the number of valence electrons in Iodine on this specific structure: in general we try to achieve the octet rule, but on this structure Iodine have 4 lone pairs and 4 single bond. Since each single bond equals to 2 electrons, doesn't Iodine have way too many electrons?

thank you
Calculating Formal Charge from Lewis Structures Assign formal charges to each atom in the interhalogen ion ICI4=; Solution St
Step 2. We assign lone pairs of electrons to their atoms. Each Cl atom now has seven electrons assigned to it, and the I atom
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