Consider the following reaction: Cl 2O5 + H20 --- 2HClO3. How much HClO3 is produced from 2.5 moles of Cl 2O5 reacting with excess water ?
Homework Answers
Q7. Correct answer is : (a.) 5.0 moles
Explanation
Balanced equation : Cl2O5 + H2O 
2 HClO3
Given : moles of Cl2O5 reacted = 2.5 mol
moles of HClO3 formed = (moles of Cl2O5 reacted) * (mole ratio of HClO3 to Cl2O5)
moles of HClO3 formed = (moles of Cl2O5 reacted) * (2 moles HClO3 / 1 mole Cl2O5)
moles of HClO3 formed = (2.5 mol) * (2 / 1)
moles of HClO3 formed = (2.5 mol) * 2
moles of HClO3 formed = 5.0 mol
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