Complete and balance the following half-reaction in basic solution
Mn2+(aq) → MnO2(s)
Step 1: Identify the oxidising and reducing agents and write half reactions
Mn2+ →MnO2 Mn2+: +2 Mn+2(-2) =0; Mn= +4
Mn2+ loses two electrons: it acts as the reducing agent as it is oxidised
Mn2+ →MnO2 + 2e- Oxidation reaction
H2O2 →H2O H2O2: 2(+1) + 2O = 0; O = -1
H2O: 2(+1) + O = 0; O = -2
H2O2 is an oxidising agent
H2O2 + e- → H2O
Thus, the balanced reaction is
Mn2+ + 2H2O2 → MnO2 + 2H2O
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