Calculate the percent ionization of 0.115 M lactic acid in a solution containing 7.5×10^-3 M sodium lactate.
Ka of lactic acid=1.4x10^-4
[Acid] = 0.115 M
[Salt] = 0.0075 M
Ka = 1.4 x 10-4
pKa = -log Ka = -log 1.4 x 10-4 = 3.854
pH = pKa + log [Salt]/[Acid]
pH = 3.854 + log 0.0075 M/0.115 M
pH = 2.668
pH = - log [H+]
[H+] = 10-pH
[H+] = 10-2.668
[H+] = 0.002146 M
% ionization = [0.002146 M/0.115 M] x 100 %
% ionization = 1.866 %
Calculate the percent ionization of 0.115 M lactic acid in a solution containing 7.5×10^-3 M sodium...
Calculate the percent ionization of 0.115 M lactic acid in a solution containing 7.5×10−3 M sodium lactate.
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