At 36°C, the decomposition of hydrogen iodide into hydrogen and iodine is a second-order reaction. The...
At 427 oC the decomposition of hydrogen iodide is second order, according to the following equation: 2Hl -> H2 +I2 In an experiment the initial [Hl]0 = 2.20 M and the rate constant is 0.00142 M-1 s-1. a) What is the half life in seconds? b) How much Hl remains after 3600 seconds have passed? c) How many minutes would it take for a concentration of 1.35 M Hl to decompose to 0.8253 M?
Hydrogen iodide gas decomposes into hydrogen gas and iodine gas at 453°C. If a 2.00 L flask is filled with 0.200 mol of hydrogen iodide gas, 0.156 mol hydrogen iodide remains at equilibrium. What is the equilibrium constant, Kc. for the reaction at this temperature? 2 HI (g) ⇌ H2 (g)+ I2 (8) 0.020 0.0062
The decomposition of hydrogen iodide on a gold surface at 150 °C HI(g)½ H2(g) + ½ I2(g) is zero order in HI. In one experiment, when the initial concentration of HI was 0.433 M, the concentration of HI dropped to 0.100 M after 1.74×10^3 seconds had passed. Based on these data, the rate constant for the reaction is M s-1.
Kc for the reaction of hydrogen and iodine to produce hydrogen iodide, H2(g) + I2(g) ⇌ 2HI(g) is 54.3 at 430°C. Determine the initial and equilibrium concentration of HI if initial concentrations of H2 and I2 are both 0.10 M and their equilibrium concentrations are both 0.052 M at 430°C
K_c for the reaction of hydrogen and iodine to produce hydrogen iodide, H_2 (g) + I_2 (g) 2HI (g) is 54.3 at 430 degree C. Determine the initial and equilibrium concentration of HI if initial concentrations of H_2 and I_2 are both 0.10 M and their equilibrium concentrations are both 0.043 M at 430 degree C. [HI]_i = M [HI]_e = M
The gas phase decomposition of hydrogen iodide at 700 K HI(g)%H2(g) + 12() is second order in HI with a rate constant of 1.20x10-'M',' If the initial concentration of HI is 1.48 M, the concentration of HI will be M after 1.34x10 seconds have passed.
Hydrogen iodide decomposes slowly to H2 and I2 at 600 K. The reaction is second order in HI and the rate constant is 9.7×10−6M−1s−1. Part A What is the half-life (in days) of this reaction when the initial HI concentration is 0.120 M ? Express your answer using two significant figures. t1/2 t 1 / 2 = days Previous AnswersRequest Answer Incorrect; Try Again; 4 attempts remaining Part B How many days does it take for the concentration of HI...
K_c for the reaction of hydrogen and iodine to produce hydrogen iodide, H_2(g)+I_2(g) doubleheadarrow 2HI(g) is 54.3 at 430 degree C. Determine the initial and equilibrium concentration of H_2and I_2 are both 0.11 M and their equilibrium concentrations are both 0.048 M at 430 degree
Hydrogen gas, iodine vapor, hydrogen iodine are mixed in a flask and heated to 642°C. H2(g) + I2(g) ⇋ 2 HI(g) Kc = 53 at 642°C If the initial concentrations of hydrogen gas and iodine vapor are both 0.054 mol/L and the concentration of hydrogen iodine is 0.130 mol/L what is the equilibrium concentration of hydrogen gas? Enter a number to 4 decimal places.
The decomposition of hydrogen iodide on a gold surface at 150 °C HI(g)½ H2(g) + ½ I2(g) is zero order in HI with a rate constant of 1.20×10-4 M s-1. If the initial concentration of HI is 0.474 M, the concentration of HI will be_________ M after 3.52×103 seconds have passed.