Hydrogen iodide gas decomposes into hydrogen gas and iodine gas at 453°C. If a 2.00 L flask is filled with 0.200 mol of hydrogen iodide gas, 0.156 mol hydrogen iodide remains at equilibrium. What is the equilibrium constant, Kc. for the reaction at this temperature?
2 HI (g) ⇌ H2 (g)+ I2 (8)
0.020
0.0062
Hydrogen iodide gas decomposes into hydrogen gas and iodine gas at 453°C
Hydrogen gas, iodine vapor, hydrogen iodine are mixed in a flask and heated to 642°C. H2(g) + I2(g) ⇋ 2 HI(g) Kc = 53 at 642°C If the initial concentrations of hydrogen gas and iodine vapor are both 0.054 mol/L and the concentration of hydrogen iodine is 0.130 mol/L what is the equilibrium concentration of hydrogen gas? Enter a number to 4 decimal places.
Gaseous hydrogen iodide is placed in a closed container at 425 ∘C, where it partially decomposes to hydrogen and iodine: 2HI(g)←−→H2(g)+I2(g). At equilibrium it is found that [HI]= 3.58×10−3 M , [H2]= 4.86×10−4 M , and [I2]= 4.86×10−4 M . What is the value of Kc at this temperature?
Hydrogen gas, iodine vapor and hydrogen iodide gas are added to an evacuated flask until the concentrations of H2 and I2 are both 2.0 M and that of HI equals 8.0M K=9.00 at 423C The reaction vessel is heated to 675 where the equilibrium concentration of the HI is determined to be 6.0M What is the K value at 675C
Kc for the reaction of hydrogen and iodine to produce hydrogen iodide, H2(g) + I2(g) ⇌ 2HI(g) is 54.3 at 430°C. Determine the initial and equilibrium concentration of HI if initial concentrations of H2 and I2 are both 0.10 M and their equilibrium concentrations are both 0.052 M at 430°C
Hydrogen iodide, HI, is formed in an equilibrium reaction when gaseous hydrogen and gaseous iodine gas are heated together. First, write the equilibrium reaction and balance it. The volume of the reactor is not changing during the process. Now, if 24.2 g of H2 and 24.2 g of I2 are heated, they form 9.9 g of hydrogen iodide, what mass of hydrogen remains unreacted? No unit is needed. At least 3 sig fig is needed. Avoid too much rounding! You...
17) What is the free energy change, ∆G°, for the equilibrium between hydrogen iodide, hydrogen, and iodine at 453°C? Kc = 0.020 2HI(g) <---> H2(g) + I2(g) 6.4 kJ 8.8 kJ 15 kJ 19 kJ 24 kJ
c for the reaction of hydrogen and iodine to produce hydrogen iodide. H2(g) + I2(g) <-> 2HI(g) is 54.3 at 430 degrees Celsius. Calculate the equilibrium concentrations of H2, I2, and HI at 430 degrees Celsius if the initial concentrations are (H2) = (I2) = 0 M, and (HI)= 0.393 M. (H2) = _______ M (I2) = _________ M (HI) = _________ M (Please explain with an ICE chart if possible.)
c for the reaction of hydrogen and iodine to produce hydrogen iodide. H2(g) + I2(g) <-> 2HI(g) is 54.3 at 430 degrees Celsius. Calculate the equilibrium concentrations of H2, I2, and HI at 430 degrees Celsius if the initial concentrations are (H2) = (I2) = 0 M, and (HI)= 0.393 M. (H2) = _______ M (I2) = _________ M (HI) = _________ M (Please explain with an ICE chart if possible.)
Be sure to answer all parts. Kc for the reaction of hydrogen and iodine to produce hydrogen iodide. H2(g) + I2(g) ⇌ 2HI(g) is 54.3 at 430°C. Calculate the equilibrium concentrations of H2, I2, and HI at 430°C if the initial concentrations are [H2] = [I2] = 0 M, and [HI] = 0.419 M. [H2] = [I2] = [HI] =
Be sure to answer all parts. Kc for the reaction of hydrogen and iodine to produce hydrogen iodide. H2(g) + I2(g) ⇌ 2HI(g) is 54.3 at 430°C. Calculate the equilibrium concentrations of H2, I2, and HI at 430°C if the initial concentrations are [H2] = [I2] = 0 M, and [HI] = 0.349 M. [H2] = M [I2] = M [HI] = M