Given: P4(s) + 3 O2(g) --> P406(s) ?H = -1640.1 kJ P4(s)+ 5 O2(g)--> P4O10(s). ?H=-2940.1...
Need Help 2. Given: Pa(s) + 3 O2(g) → P.O(s) AH = -1640.1 kJ Pa(s) + 5 O2(g) → P4010(s) AH = -2940.1 kJ Use Hess Law to calculate the AH for P.O(s) + 2O2(g)→ P4010(s)
32. Given the following data: A. P4(s)+ 6 Cl2(g)4 PCls(g) B. P4(s)+ 5 02(g) P4O10(s)AH=- 2967.3 C. PCls(g)+Cl2(g) PCIS(g) D. PCI3(g)+O2(g) ClaPO(g) AH-285.7 AH 1225.6 kJ AH=-84.2 Calculate AH for the reaction: P4O10(s)+6 PCI5(g) 10 CI3PO(g). Note when I solved this problem, I used 3 of the 4 data reactions, added them together, then used the fourth data reaction to get to the desired reaction. -B-6C+10D+A
Calculate the value of ΔH° for the following reaction: P4O10(s) + 6PCl5(g) ---> 10Cl3PO(g) P4(s) + 6Cl2(g) ---> 4PCl3(g) ΔH° = -1225.6 kJ P4(s) + 5O2(g) ---> P4O10(s) ΔH° = -2967.3 kJ PCl3(g) + Cl2(g) ---> PCl5(g) ΔH° = -84.2 kJ PCl3(g) + (1/2)O2(g) ---> Cl3PO(g) ΔH° = -285.7 k please explain well i do not understand these kind of problems
Calculate the standard entropy change for the reaction P4(g)+5O2(g)→P4O10(s) using the data from the following table: Substance ΔH∘f (kJ/mol) ΔG∘f (kJ/mol) S∘ [J/(K⋅mol)] P4(g) 58.9 24.5 279.9 O2(g) 0 0 205.0 P4O10(s) −2984 −2698 228.9
Express the equilibrium constant for the following reaction. P4(s) + 5O2(g) ⇌ P4O10(aq) K =___ A. A) = [P4O10] / [P4] B. B) = [P4O10] / [P4][O2]5 C. C) = [P4O10] / [O2]5 D. D) [O2]-5 E. E) none of these
to two e tem- metal. e after capac- 5.63 Calculate the enthalpy change for the reaction P406(s) + 202(8) — P4010(s) given the following enthalpies of reaction: P4(s) + 3 02(8) - PO6(s) AH = -1640.1 kJ P4(s) + 502(8) —— P4010(s) AH = -2940.1 kJ solves
Assume all reactants and products are gases unless noted otherwise. Given the following data; P4(s) + 6Cl2 → 4PCl3 ∆H = -1225.6 kJ P4(s) + 5O2 → P4O10(s) ∆H = -2967.3 kJ PCl3 + Cl2 → PCl5 ∆H = -84.2 kJ PCl3 + 1/2O2 → Cl3PO ∆H = -285.7 kJ Calculate ∆Hrxn for the following reaction. P4O10 + 6PCl5 → 10Cl3 PO
3(20 pts) Consider the data: P4(s) + 6 Cl2(g) ----> 4 PC13(g) P4(s) + 5 O2(g) -----> P4010(s) PC13(g) + Cl2(g) ---> PCls(g) PC13(g) + 1/2O2(g) ----> C13PO(g) AH° (kJ/mol) -1226.6 -2967.3 -84.2 -285.7 Using only the above reaction data, compute the AHX of P4010(s) + 6 PCls(8) ----> 10 C13PO (g)
Given the following data: P4(s) + 302(9) - P406(5) AH = -1640.1 k) P406(s) + 202(9) - P4010(s) AH = -1300 k] Find the AH of the following reaction: P4(s) + 502(9) - P4010(5)
1. Calculate the quantity of heat released when 8.Sg of hydrogen peroxide decomposes, given: atomic weights 0=16, and H= 1. Hydrogen peroxide decomposes to water and oxygen according to the reaction: H = -196KJ 2. Given the speclflc heat, c,, of water Is 4.18 J/g 0c,how much heat Is needed to warm 200g of water from 22°c to 98°C? q=mC,AT 3. If 20.9KJ of heat were added to 250g of liquid water, how much would its temperature Increase? (Use 4.18 J/goc...